Question
Segmentation error :( how do I fix this in my code and need help adding just the regular program stock.x runs normal program regular program
Segmentation error :( how do I fix this in my code and need help adding just the regular program
stock.x runs normal program regular program
stock.x 13 is on command line run prgram
stock.x 13 26 13 is on command line but with spaces run program
stock.x 13, 26, 13, 40 is on command line but with commas run program
#include
#include
#include
#include
#include "io.h"
#include "io.c"
#include "stats.h"
#include "stats.c"
int main(int argc, char* argv[])
{
int size, i;
char order;
//user has enter nothing in command prompt
float *array;
if(argc
{
//from Proj 3 greet and read data
// greet and get the stock values
print_greeting();
printf("How many stocks prices would you like to analyze? ");
scanf("%d", &size);
// read the data
array = (float *)malloc(size*sizeof(float));
read_array(array, size);
}
//user has enter only one argument
else if(argc=1)
{
//user enters one value
//check whether the argument is numeric
}
//user enters a value seperated by ','
//assume the delimeter is a ','
else if(argv[1]=",")
{
//count the number of entries
//allocate the values into array
/eed to use a single pointer to allocate the values into array, but how?
int i;
for (i = 0; i
{
//parse the input string and store the value into arrays
float * parseString(char str[])
{
float *result = (float*)malloc(10*sizeof(float)); // declaring result array, using max size for size
char *token = NULL;//intializing token to split
int count=0;
char *unconverted;
for(token = strtok(str,","); token != NULL; token = strtok(NULL, ","))
{
//strtok splits string according to the delimeter which is ,
result[count]=strtod(token, &unconverted);//adding to the result array, strtod, converts the token char* to float
count++;
}
return result;//returning result
}
{
size=atoi(argv[i]);
}
}
}
//user enters the number of entries
else
// get the number of entries
{
//allocate the values into array
int i;
for (i = 0; i
{
}
}
// same as from project 3
//get the stats
float mean = get_average(array, size);
float variance = get_variance(array, size);
float min = get_min(array, size);
float max = get_max(array, size);
float median = get_median(array, size);
// show the results
print_results(array, size, median, min, max, mean, variance);
return 0;
}
stats.h
#ifndef STATS_H #define STATS_H void sort (float output[], int size, char order); float get_average(const float array[], int size); float get_variance(const float array[], int size); float get_median(const float array[], int size); int get_max(const float array[], int size); int get_min(const float array[], int size); int get_num_tokens(const char str[], char delim); #endif
stats.c
#include
// sorts the values of an array according to order void sort (float output[], const int size, char order) { int i, j; float temp;
if (order == 'a' || order == 'A') { for ( i = 0; i output[j] ) { temp = output[i]; output[i] = output[j]; output[j] = temp; } } else if (order == 'd' || order == 'D') { for ( i = 0; i
}
// calculates the mean of the elements of an array float get_average(const float array[], int size) { int i; float sum = 0.0;
for (i = 0; i
sum /= size;
return sum; }
// calculates the variance of the emelemts of an array // this function calls the get_average to get the mean float get_variance(const float array[], int size) { int i; float sum = 0.0;
float mean = get_average(array, size);
for (i = 0; i
sum = sum/size - mean*mean;
return sum;
}
// gets the median of an array after it sorts it float get_median(const float array[], int size) { int i; float temp_array[size]; // temp array tp be manipulated float median;
// copy oroginal array to the temp array for (i = 0; i
sort(temp_array, size, 'a');
if (size % 2 == 0) median = (temp_array[size/2] + temp_array[size/2-1])/2.0; else median = temp_array[size/2];
return median; }
// finds the maximum value of the elements of an array int get_max(const float array[], int size) { int i; float max = array[0];
for (i = 0; i = max) max = array[i];
return max; }
// finds the minimum value of the elements of an array int get_min(const float array[], int size) { int i; float min = array[0];
for (i = 0; i
return min;
}
io.h
#ifndef IO_H #define IO_H
void read_array(float array[], int size); void print_greeting(void); void print_array(const float array[], int size); void print_results(const float array[], int size, float median, float min, float max, float mean, float variance);
#endif
io.c
#include
// prompt the user for input and read the values into an array void read_array(float array[], int size) { int i = 0; for (i = 0; i
// say hi to the user void print_greeting(void) { printf("Welcome! Today we are reading and analyzing stocks. "); }
// display array values void print_array(const float array[], int size) { int i = 0;
for (i = 0; i
printf(" ");
}
// print the stat results including input data void print_results(const float array[], int size, float median, float min, float max, float mean, float variance) {
printf(" Say something here about the ouput "); print_array(array, size); printf("median: $%.2f ", median); printf("min: $%.2f ", min); printf("max: $%.2f ", max); printf("variance: $%.2f ", variance); printf("mean: $%.2f ", mean);
}
Algorithms Data: Stock prices input in several ways Result: mean, variance, min, max, and median of input data i begin 2 if the user enters nothing on the command line then This is the modified Project 3 greet and read the data; 4 end else if they enter one value then if it's a single number then Implement the mdified Project 3 logic in reading the data; end else assume the delimiter is a: count the number of entries; allocate array parse the input string and store the values into arrays 12 13 14 end end 16 else get the number of entries put each entry into an array 18 19 end 20 end 21 Now you should have the array populate 22 The same as project 3 from this point forward; Algorithm 1: Gather the data from the user then process How to run the code $./stocks .x # conditional online 2 $ ./stocks.x 13 # conditional on line 6 $ ./stocks .x 12.5,11.31 ,12,22.43 , 23.1,31 ,12,11,11.11 # conditional o /stocks . x 12.5 11.31 12 22.43 23.1 31 12 11 11.11 # conditional oStep by Step Solution
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