Show calculation to get credit. When 50.0 mL of 0.05 0.0500M NaOH in a coffee cup calorimeter, the temperature of the water increases by 10.0C, (AT). Calculate the heat of the reaction of HCV/mole for the following thermochemical equation: HCl(aq) + NaOH(aq) NaCl(aq) + HO(1) [Specific heat of HO is 4.18 J/g C).]Assume that the density of water is 1.0 g/mL]. a. -57,300 J/mol b. -2870 J/mol C. +2870 J/mol d. +57,300 J/mol none of these e