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Show every detailed step and explain. The mean and standard deviation of the length of a machined part are 59mm and 1.1mm. %%Find the 95%

Show every detailed step and explain.

The mean and standard deviation of the length of a machined part are 59mm and 1.1mm. %%Find the 95% confidence interval for this sample? %%What is the assumption you made in this calculation? Hint: It has normal distribution! n>30

use E=Z alpha/2 * sigma

alpha = 0.5

alpha/2 = 0.025

mean = 59

SD = 1.1

%%find Zscore.

Thank you very much!

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