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$($a$)$ Create a vector from $10$ to $1000$ containing all multiples of $5.$

$($b$)$ Create a vector of values from $-2$ to $2$ with a step size of $\frac{}{20}.$

$($c$)$ Create a vector containing $20$ values, evenly spaced between $80$ and $100.$ What should you use, colon $($ : $)$ or linspace?

In direct current applications, electrical power is calculated using Joule's law as

$P=I^{2}R$

where $P$ is power in watts, I is the electrical current, measured in amperes, and $R$ is resistance measured in ohms. The resistance of a conductor of uniform cross section $($a wire or rod for example$)$ is

$R=\frac{l}{A}$

where, $($rho$)$ is the electrical resistivity measured in ohm$-$meters, $l$ is the length of the wire, $A$ is the cross$-$sectional area of the wire. This results in the equation for power

$P=I^2\frac{l}{A}$

Electrical resistivity is a material property that has been tabulated for many materials. For example:

Material

Iron

Gold

Copper

Aluminum

$($ohm$-$meters$)$

$1\mathrm{.}0{10}^{-7}$

$2\mathrm{.}44{10}^{-8}$

$1\mathrm{.}68{10}^{-8}$

$2\mathrm{.}82{10}^{-8}$

Write the Matlab code to calculate the power that is dissipated through a wire with the following dimensions for each of the materials listed $($use Eq$.3).$ Put all values of $$ in a matrix$/$vector$.$

diameter, $d$

$0\mathrm{.}004m$

length, $l$

$1\mathrm{.}2m$

Assume the wire carries a current of $I=5$ amps. The cross$-$sectional area of the wire is given by $A=(\frac{d}{2}{)}^2.$