show work and explain

[5] A projectile is launched horizontally through a tube of length & from the top of a cliff of height h, as depicted in Vo -a the sketch. It starts with an initial velocity vo , but as it passes though the tube friction causes it to slow with h constant acceleration -a. Once it exits its horizontal acceleration vanishes ( a, = 0), but then it has a vertical acceleration of a, = -g due to the downward gravitational R V force. When it hits the ground, its velocity is at an angle 9 with respect to the horizontal. a) Find the net horizontal range, R , it travels, relative to the base of the cliff (express R in (a) R= terms of v., a, g. h and (). b) What value of the tube length, C., produces the (b) C. = maximum range R? (Hint: set dR / d( =0) c) For this value (., find tan0 = v. /v. . (c) tan 0 =