Sodium hydroxide reacts with carbon dioxide as follows:

$2$NaOH$(s)+C{O}_2(g)N{a}_{2}C{O}_3(s)+H_{2}O(l)$

When $6\mathrm{.}68$molNaOH and $3\mathrm{.}01molC{O}_2$ are allowed to react, how many moles of $N{a}_{2}C{O}_3$ can be produced?

Hint: This is a question about limiting reactant.

$3\mathrm{.}01$

$6\mathrm{.}02$

$3\mathrm{.}34$

$13\mathrm{.}4$