Solid lead reacts vigorously with aqueous solutions of hydrochloric acid to form hydrogen gas $($which is diatomic$)$ and a precipitate of lead$($II$)$ chloride.

Doug performed this reaction using $5\mathrm{.}00$ g of solid lead and a $1\mathrm{.}50$ M hydrochloric acid solution.

$1.$ How many mL of $1\mathrm{.}50$ M hydrochloric acid would Doug need to completely react with the $5\mathrm{.}00$ g of solid lead he used in his reaction.

$2.$ How many grams of the lead$($II$)$ chloride precipitate would his reaction create when the $5\mathrm{.}00$ g of solid lead he used completely reacts with the appropriate volume of $1\mathrm{.}50$ M hydrochloric acid.