Solve this using R programming language:

Copy-and-paste the following matrix directly into R, A = matrix( ((1:25) * (1:25))%%11, nrow = 5, ncol = 5) Note, the %% syntax stands for "mod". Basically, what we are saying is that the entries in the matrix get computed mod 11. calculate the row-reduced version of A with- out dividing the pivots. Call the reduced matrix Ar. If you did this correctly you will notice that det(A) = det(Ar), as this type of row-reduction does not change the determinant. Warning: If you get that det(A) det(Ar) then it might be because you accidentally divided the very last row. The last row pivot should not be equal to 1. If it is equal to one then your code incorrectly divides out that pivot, which in term leads to the wrong answer. In the box below input the value of sum (A.r).