STARTING AMOUNT 1 pl 0 How many moles of KCIO3 must be reacted according to the following balanced ADD FACTOR -89.4 X x( ) 122.55 g KCIO3 2 KCIO3(s) X 74.55 chemical reaction to transfer -34.2 -34.2 g KCI 1530 2 KCl(s) + 3 3.6 0.765 6.022 103 g 0 32.00 = J kJ of heat? O(g) AH = -89.4 ANSWER 3060 2 mol KCI kJ 1000 RESET 0.001 KJ 2 3 0.383 mol KCIO3