Starting from rest at a height equal to the radius of the circular track, a block...

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Starting from rest at a height equal to the radius of the circular track, a block of mass 22 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient ). The radius of the track is 41 m. te The acceleration of gravity is 9.8 m/s. 22 kg 0 41 m If the kinetic energy of the block at the bottom of the track is 6200 J, what is the work done against friction? Answer in units of J. Starting from rest at a height equal to the radius of the circular track, a block of mass 22 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient ). The radius of the track is 41 m. te The acceleration of gravity is 9.8 m/s. 22 kg 0 41 m If the kinetic energy of the block at the bottom of the track is 6200 J, what is the work done against friction? Answer in units of J.

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To solve this problem we can begin by calculating the speed of the block at the bottom of the track ... View the full answer