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step by step please The depicted pulley system consists of a rod (mass mr, length L ), a triangular body (mass mT ), a ball

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The depicted pulley system consists of a rod (mass mr, length L ), a triangular body (mass mT ), a ball (mass mb ), a wheel (radius rw and mass mw ), a spool (outer radius Rc, inner radius rc, mass mc ) and a massless pulley. All components are connected by a massless rope. The whole system is considered frictionless and there is no slip. Use the given positive directions for the movement of the bodies. Round the results to one decimal place! Example: 6.746=6.7 or 6.756=6.8 d) Calculate the rope force T3 for a measured vertical reaction force NYD=175N (Point D): (3P) (1N e) Calculate the moment of inertia of the rod around its turning Point A and the rope force T1 between rod and wheel: (6P) (5)nr2L2 (2) N f) Calculate the rope force T2 using T3=600N : (6P) (4N g) Calculate the vertical reaction force at the bearing of the rod (Point A ): (3P) Use T1=250N. Ny= (3kg Given parameters: mT=75kgmr=40kgmc=60kgL=1m=0.6m/s2Rc=0.5mrc=0.25mJc=1/3mcRc2g=9.8m/s2

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