Structural Chemistry, Semester 1, 2021/2022 [CHY2010] A2. The reaction between the tetraphosphine 4, Fe(BPh:), and NaH gives a diamagnetic compound of empirical formula C6H63BFeP4 (A). The 'H NMR spectrum of A exhibits signals due to phenyl and CH, protons, along with a complex multiplet at -11.7 ppm, the relative intensity of this high- field signal compared to the signals due to the CH, and phenyl protons is 1:12:50. The 31p'H NMR spectrum of A consists of a pair of triplets of equal intensity at 119.3 and 99.4 ppm, respectively (J = 24.5 Hz). Using these data, answer ALL parts (a) to (c) [NOTE: coupling to Fe isotopes should be neglected in your answer). (a) Draw a structure for A which is consistent with the data provided and account for the 3lp H NMR spectrum of this compound. [50%]