Question
SUMMARY OUTPUT Regression Statistics Multiple R0.420288912 R Square0.17664277 Adjusted R Square 0.174563585 Standard Error 2.505457775 Observations 398 ANOVA dfSMSFSignificance F Regression 1533.3065575533.306557584.957700251.82309E-18 Residual 3962485.8181916.277318665 Total
SUMMARY OUTPUT
Regression Statistics
Multiple R0.420288912
R Square0.17664277
Adjusted R Square 0.174563585
Standard Error 2.505457775
Observations 398
ANOVA
dfSMSFSignificance F
Regression 1533.3065575533.306557584.957700251.82309E-18
Residual 3962485.8181916.277318665
Total 3973019.124749
CoefficientsStandard Errort Stat P-valueLower 95%
Intercept12.08113320.39860872930.308250473.1867E-10511.29747935
Upper 95%Lower 90.0% Upper 90.0%
12.8647870411.4239427612.73832363
X Variable 10.1482892020.0160882269.2172501461.82309E-180.116660191
Upper 95%Lower 90.0% Upper 90.0%
0.1799182140.1217643740.174814031
Among the many attributes of cars that impact fuel efficiency, the ability to accelerate from 0-to-60 MPH is rarely discussed. Download that data set that follows. Then run a regression analysis predicting fuel efficiency as measured by MPG based on Acceleration time as a predictor.Your results will be used in the next several problems.
1)How much correlation is there between the variables?
Round to three decimals and use leading zeros if necessary.
2)How much of the variability in MPG is explained by acceleration?
Round to three decimals and use leading zeros if necessary.
3) What is your decision regarding the null hypothesis of1?
Reject the null becausep> 0.05.
Reject the null becausep< 0.05
Fail to reject the null becausep> 0.05
Fail to reject the null becausep< 0.05
4) What are the degrees of freedom for the t-test of 1?
5) Using only the confidence interval approach, at = 0.05, the conclusion about the1hypothesis test is:
Reject the null hypothesis because the value of the null is outside the interval.
Reject the null hypothesis because the value of the null is inside the interval.
Fail to reject the null hypothesis because the value of the null is outside the interval.
Fail to reject the null hypothesis because the value of the null is inside the interval.
6) What is the 90% confidence interval around 1?
0952902 - 8.986684
0937129 - 1.44528
1.601134 - 8.338452
0.978131 - 1.404278
7) How are the degrees of freedom error computed?
n
n-1
k
k-1
n-k
n-k-1
8) At = 0.05, is the overall model significant?
No, F* < Fc
The test is inconclusive because 0.05 <p< 0.10
Yes, F* < Fc, andp< 0.05.
Yes, F* > Fc, andp< 0.05.
Yes, F* > Fc, andp> 0.05.
9) What is your decision about the null hypothesis for the overall model?
Reject the null
The test is inconclusive
Fail to reject
10) The model of the data is described by=+*x
Round each entry to three decimals.
11) Ifxis increased by one unit, how much doesy-hat increase?
Round to three decimals.
12) Predict the value of y given acceleration is 10.75.
Round to three decimals.
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