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Posted on Oct 14, 2024

=sum_(t=1)^(n=25) ((180)/((1+0.10)^(t)))+(1000)/((1+0.10)^(25))

=\sum_(t=1)^(n=25) ((180)/((1+0.10)^(t)))+(1000)/((1+0.10)^(25))

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