Suppose a student either has 1, 2, or 3 finals to take each with a respective probability of 0.19, 0.47, and 0.34.

Q1: What is a student's expected number of finals?

Q2: What is the standard deviation?

sum of x =1+ 2+ 3 = 6

sum of x^2= 1 + 4 + 9 = 14

p = 1/3 (this may be super wrong)

E(X)= 6 * (1/3) = 2

Var(X)= 14 * (1/3) - [2]^2 = .66667

st.dev= sqrt of var(X) = .816499