Suppose that $1\mathrm{.}15$ g of rubbing alcohol $($propan$-2-$ol$)$ evaporates from a $65\mathrm{.}0$ g aluminum

block. If the block is initially at $25\backslash$deg C$,$ what is the final temperature of the block after the

evaporation of the alcohol? $($Assume that the heat required for the vaporization of the alcohol

comes only from the aluminum block and that alcohol vaporizes at $25\backslash$deg C$,$ aluminum$$s specific

heat capacity $($Cs$)$ is $0\mathrm{.}903$ J$/\backslash$deg C$.$g$)$