Suppose that continuous random variable X has the following PDF: fx(x) =x219 for 0 Sx

Suppose that continuous random variable X has the following PDF: .fA(x) = .e / 9 for 3. If random variable Y = 2X, what is the PDF of Y, fy(y)? a. / 72 b. / 72 c. 8y2 / 9 d' Y2/ 18 y2/ 18 for 0 fy 3 for 0 Sy 6 for 0 fy 3 for 0 S y 6 for 0 3 f. None of the other answers are correct. g. 42/9 h' y2/ 36 8)P/9 2y2 / 9 k. 4y2 / 9 l. 2y2/9 m. Y2 / 36 for 0 s y 3 for 0 S y 3 for 0 fy 3/2 for 0 S y S 3 for O 3/2 for 0 Sy 3/2 for 0 fy 6