Question
The below, python dictionary (my_fruits_dic) holds fruits and their price. my_fruits_dic = { Fruit: Price, apple: 6.44, banana: 0.77, orange: 3.44, } --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (1) Add
The below, python dictionary (my_fruits_dic) holds fruits and their price.
my_fruits_dic = {
"Fruit": "Price",
"apple": 6.44,
"banana": 0.77,
"orange": 3.44,
}
---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
(1) Add a new item "berries" with the value {blackberry: 1.24, blueberry: 3.14}.
Print myDic. (This new dictionary will be added without the berries key. It needs to be added as a nested dictionary under berries key).
(see screenshot to see if my code/output to this question is correct. Please provide any other of your input/ideas/knowledge.
Input code: my_fruits_dic - { "Fruit": "Price", "apple" : 6.44, "banana": 0.77, "orange": 3.44, } berries = { "Name": "Quantity", "blackberry": 1.24, "blueberry": 3.14, } mydic - "thisdic" : my_fruits_dic, "berries" : berries, } int (mydic) Output Answer: >>> my_fruits_dic - { "Fruit": "Price", "apple": 6.44, "banana": 0.77, "orange" : 3.44, } >>> berries - "Name" : "Quantity", "blackberry": 1.24, "blueberry": 3.14, >>> mydic - { "thisdic" : my_fruits_dic, "berries" : berries, >>> print (mydic) {"thisdic': {'Fruit': 'Price', 'apple : 6.44, "banana': 8.77, orange": 3.44}, "berries': {"Name" : 'Quantity', 'blackberry': 1.24, blueberry': 3.14}} >>> 0 Is this method/way of doing it correctStep by Step Solution
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