The cumene process is used to convert benzene and propene in the presence of oxygen to phenol and acetone via the reaction CH+CH +0, C,H,OH + C,H,O This reaction is carried out with excess benzene and excess oxygen to ensure that no side reactions occur. A 1.25 ratio of benzene to propene is fed to a reactor in the presence of 34,5% excess air (N, and 0,). The first pass conversion of propene is 100%. The products leave the reactor and enter a condenser where the gaseous nitrogen and oxygen leave the process and the liquid organic products are fed to a distillation column. The distillation column separates the products from the reactants. Any unreacted reactants are fed into the fresh feed stream. The products are directed to a second distillation column that separates the acetone from the phenol. If 21.4 kg/hr of phenol is produced from this process, answer each of the questions. First, label the process flow diagram, putting either a given numeric value or the words "unknown" or "none" in cach space. Do not leave any spaces blank. Variable names are shown for reference later. mol/hr First, label the process flow diagram, putting either a given numeric value or the words "unknown" or "none" in each space. Do not leave any spaces blank. Variable names are shown for reference later. mol/hr X1 mol CH /mol 34.5 mol CH /mol Fresh feed n=1 345 mol/hr Reactor feed n=1 345 mol/hr n- 345 molhr ng 445 molhr Distillation column 1 Reactor Condenser 125 X- 1.25 mol CH /mol molCH/mol eto n=214 mol gas/hr ** 0.79 mol CHF /mol X- mol CH /mol mol O, mol mol Omol mol O2/mol 214 mol CH 0/hr mol N/mol N mol N/mol mol N/mol n, 21.4 mol/hr * 214 mol CH 0/mol X 214 Distillation column 2