The dry weight of a rock is measured to be 211.6g, and its saturated weight is measured to be 219.4g. The rock has a length of 6.5cm, a diameter of 3cm, and a porosity of 18.5%. Given that the rock contains only water (w=1.02g/cm3) and oil (0=0.84g/cm3), calculate the water and oil saturations. Question 5.4 Solvent extraction was used in order to measure the fluid saturation in a core. Question 5.5 The following data are given for the core: A core contains only oil and water within it. Find the water and oil saturations by - Length: 3.5 inches using the following data: - Diameter. 2 inches - Dry weight: 168.3g - Porosity: 22.9% - Saturated weight: 203.2g - Initial weight of the core: 487.6g - Weight of the core after water removal: 184.1g - Final dry weight of the core: 455.9g - Dlameter; 3.62cm - Water volume measured: 14.23cm3 - Length: 6.92cm - Water density. 1.04g/cm3 - Water density: 1.03g/cm3 - Oil density: 0.80g/cm3 Calculate the fluid saturations. Question 5.6 A Dean-Stark apparatus was used to determine the fluid saturations in a cylindrical core of diameter 3cm, length 5.8cm, and porosity 15.2%. The initial weight of the core prior to extraction was measured to be 151.6g. The weight of the core plug after it was extracted and dried was 146.3g. The volume of water recovered from the core in the experiment was 2.94cm3. The densities of reservoir water and oil are 1g/cm3 and 0.86g/cm3, respectively. Determine the initial fluid saturations in the core