Question
The Dynaco Manufacturing Company produces a product in a process consisting of operations of five machines. The probability distribution of the number of machines that
The Dynaco Manufacturing Company produces a product in a process consisting of operations of five machines. The probability distribution of the number of machines that will break down in a week follows:
Machine Breakdowns per week | Probability |
0 | 0.10 |
1 | 0.10 |
2 | 0.20 |
3 | 0.25 |
4 | 0.30 |
5 | 0.05 |
Every time a machine breaks down at the Dynaco Manufacturing Company, either1, 2, or 3 hours are required to fix it, according to the following probability distribution:
Repair time (hour) | Probability |
1 | 0.30 |
2 | 0.50 |
3 | 0.20 |
Conduct a simulation for 10 weeks using the random numbers provided below to determine the machine breakdowns per week as well as the repair time. Compute the weekly average number of machine breakdowns and the weekly average repair time. If it costs $50 per hour to repair a machine when it breaks down (including lost productivity), determine the average weekly breakdown cost.
Use the following random numbers in order (from left to right) for the simulation of number of machine breakdowns per week:
0.13 | 0.21 | 0.97 | 0.09 | 0.26 | 0.47 | 0.62 | 0.89 | 0.76 | 0.24 |
Use the following random numbers in order (from left to right, first row first - as you need them) for the simulation of repair time for each machine breakdown.
0.19 | 0.39 | 0.07 | 0.42 | 0.65 | 0.61 | 0.85 | 0.40 | 0.75 | 0.73 | 0.16 | 0.64 |
0.38 | 0.05 | 0.91 | 0.97 | 0.24 | 0.01 | 0.27 | 0.69 | 0.18 | 0.06 | 0.53 | 0.97 |
0.13 | 0.21 | 0.97 | 0.09 | 0.26 | 0.47 | 0.62 | 0.89 | 0.76 | 0.24 | 0.10 | 0.90 |
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