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The equation is 10=5x-15ln(x)+4y-6ln(y) dy/dx=5y(3-x)/2x(2y-3) Question 1 1 pts Match the derivative value with its meaning about the function in the video. @ = 0

The equation is 10=5x-15ln(x)+4y-6ln(y)

dy/dx=5y(3-x)/2x(2y-3)

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Question 1 1 pts Match the derivative value with its meaning about the function in the video. @ = 0 J [Choose] d3 Minimum or maximum number of sardines. d We expect that in the nearfuture, when there are 4.5 million sardines, there will be approximately 520 sharks. y , . . . a does not EXISt Minimum or maXImum number of sharks. We expect that in the nearfuture, when there are 4.5 million sardines, there will be approximately 400 sharks. aim 0 We expect that in the nearfuture, when there are 450 sharks, there will be approximately 4 million sardines. dy 7 We expect that in the nearfuture, when there are 450 sharks, there will be approximately 5.2 million sardines. aim d does not exist [Choose] 6 1!} y(5) = 4.6 and y'(5) = 1.2 [Choose] Question 2 2 pts Suppose the population of sardines is currently 6 million, and the population of sharks is 367. Use y to estimate what the population of sharks will be if the da: population of sardines decreases to 5 million. Notes: 0 You are not estimating the value on the graph, you are estimating using the derivative 0 Remember that y represents the population of sharks in hundreds 0 Your answer should be correct to one decimal place

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