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The expected value for a question was: E(X) = ( 1 / t h e t a ) ( ( e 5 6 ) /

The expected value for a question was:

E(X) =( 1 / t h e t a ) ( ( e56 ) / ( and51))

Using the E(X) above, comapre this expected value with the expected value of the Expo(theta) distribution, and comment.

Hint: the eponential distribution has E(x)=1/theta

What comments would I make about this?

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