The following 5 questions are based on this information. In a random sample of 300 students of class 2016, 60% (p=0.6) were Americans. The goal isto construct a 90% confidence interval of the proportion (p) of all students who were Americans in the class of 2016

1)The standard error (SE) of pis

2)The critical value (CV) needed for the 90% confidence interval estimation of pis

3)The 90% confidence interval estimate of pis

4)Suppose around the period the above sample was taken, Principal of the school claims that 69% of all students were Americans. In light of the sample evidence and at the 10% level of significance, reject?

5)A Journalist wishes to collect new random sample with the aim of building a new confidence interval at the 90% confidence level for p. Using the current sample proportion (from the 300 students) as a basis, what sample size (n) would the journalist require to achieve a 10% margin of error?

please show step by step, equations . dumbproof it to the best of your ability

please dont type like this P[ |X(bar)-| <25] =P[ |(X(bar)-)/(/sqrt(n))| <25>