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The following instruction is stored at 0x00600000. addi $t1, $t2, 4 Assume $t1 = 0x00000001, $t2 = 0x00000002 When this instruction completes the ID stage,
The following instruction is stored at 0x00600000.
addi $t1, $t2, 4
Assume $t1 = 0x00000001, $t2 = 0x00000002
When this instruction completes the ID stage, what is the value of Read data 2 written into the ID/EX register?
A. 0x00000000
B. 0x00000002
C. 0x00000001
D. 0x00000004
please show work so I understand how it is done. thank you
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