The frame shown has a distributed load of w=85 lb/ft and a point load P = 190 lb at an angle from verticle of 0=25. Calculate the internal loadings on the cross sections at H and at E. G H 4 ft A B 1ft W E D 1 ft 2 ft 1 ft 2 ft 1 ft The internal normal load at H is N = 1210 The internal shear load at H is V = 0 The internal bending moment at H is M = 0 lb. lb. LL F o lb-ft. The internal normal load at E is N = 95 x lb. The internal shear load at E is V = 250 x lb. The internal bending moment at E is M = 215 lb-ft. P