The freezing point of water, H20, is 0.00C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is sucrose A student dissolves 10.86 grams of sucrose, C12H2011 (342.3 g/mol), in 294.8 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Ko ("C/m) Kp (C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCI 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH CH OCH CH3 2.02 The molality of the solution is m. The freezing point of the solution is C. The freezing point of water H,0 is 0.00C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is sucrose. How many grams of sucrose, C12H22011 (342.3 g/mol), must be dissolved in 203.0 grams of water to reduce the freezing point by 0.300C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Ku (*C/m) Ky("C/m) Water H20 0.512 1.86 Ethanol CH2CH OH 1.22 1.99 Chloroform CHCI 3.67 Benzene CH 2.53 5.12 Diethyl ether CH3CH2OCH CH3 2.02 g sucrose