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The maximum distance s and the maximum height h that a projectile shot at an angle are given by s=(v_(0)^(2))/(g)sin(2theta );h=(v_(0)^(2)sin^(2)(theta ))/(2g) Determine value
The maximum distance
s
and the maximum height
h
that a projectile shot at an angle are given by\
s=(v_(0)^(2))/(g)sin(2\\\\theta );h=(v_(0)^(2)sin^(2)(\\\\theta ))/(2g)
\ Determine value of
s
and
h
for:\
\\\\theta =15\\\\deg ,25\\\\deg ,35\\\\deg ,45\\\\deg ,55\\\\deg ,65\\\\deg ,75\\\\deg ;v_(0)=100(m)/(sec and g)=9.81(m)/(sec^(2))
\ Script
o.
\ tetha_1=15:10:75\
v0=100;g=9.81
;\
%s=
\
%h=
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