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The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received

The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received is

85.6

seconds. A manager devises a new drive-through system that

she

believes will decrease wait time. As a test,

she

initiates the new system at

her

restaurant and measures the wait time for

10

randomly selected orders. The wait times are provided in the table to the right. Complete parts (a) and (b) below.

102.9

80.5

69.0

96.2

58.5

87.7

76.2

72.9

64.8

81.3

LOADING...

Click the icon to view the table of correlation coefficient critical values.

(a) Because the sample size is small, the manager must verify that the wait time is normally distributed and the sample does not contain any outliers. The normal probability plot is shown below and the sample correlation coefficient is known to be

r=0.993.

Are the conditions for testing the hypothesis satisfied?

Yes,

No,

the conditions

are

are not

satisfied. The normal probability plot

is

is not

linear enough, since the correlation coefficient is

less

greater

than the critical value. In addition, a boxplot does not show any outliers.

607590105-2-1012Time(sec)Expectedz-score

A normal probability plot has a horizontal axis labeled Time (seconds) from 50 to 115 in increments of 5 and a vertical axis labeled Expected z-score from negative 2 to 2 in increments of 0.5. Ten plotted points closely follow the pattern of a line that rises from left to right through (58.5, negative 1.55) and (96, 1). All coordinates are approximate.

(b) Is the new system effective? Conduct a hypothesis test using the P-value approach and a level of significance of

=0.01.

First determine the appropriate hypotheses.

H0:

mu

pp

sigma

equals=

greater than>

not equals

less than<

85.6

H1:

mu

pp

sigma

greater than>

not equals

less than<

equals=

85.6

Find the test statistic.

t0=nothing

(Round to two decimal places as needed.)

Find the P-value.

The P-value is

nothing.

(Round to three decimal places as needed.)

Use the

=0.01

level of significance. What can be concluded from the hypothesis test?

A.

The P-value is

greater

than the level of significance so there

issufficient

evidence to conclude the new system is effective.

B.

The P-value is

less

than the level of significance so there

issufficient

evidence to conclude the new system is effective.

C.

The P-value is

greater

than the level of significance so there

isnotsufficient

evidence to conclude the new system is effective.

D.

The P-value is

less

than the level of significance so there

isnotsufficient

evidence to conclude the new system is effective.

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