What is the enthalpy change for the unknown reaction? P(s) + 3/2Br2() ( PBr3() H = 185
Question:
P(s) + 3/2Br2(ℓ) ( PBr3(ℓ)
ΔH = −185 kJ
PI3(s) ( P(s) + 3/2I2(s)
ΔH = ?
PI3(s) + 3/2Br2(ℓ) ( PBr3(ℓ) + 3/2I2(s)
ΔH = −139 kJ
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The unknown reaction has PI 3 as a reactant P and I2 as the products So if we reverse the f...View the full answer
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