The most important measure in any business is a successful purchase of their product. Task success is a discrete measure (0 is fail, 1 is successful purchase). The following table shows a discrete distribution across 100 clients for product purchase. . Table 4 X (purchase success) 0 1 2 3 P(probability purchase) 0.1 0.3 0.2 0.4 v Calculate the expected value for table4? A. 4.620 Calculate the discrete variance for table 4? B. 0.1101 What is the binomial probability that you find less than 11 clients who will C. 1.04 buy your extended warranty if you present to 79 clients, and the probability of a client buying a warranty after your presentation is 20%? D. Cannot calculate without more information What is the binomial expected value a client buys your extended warranty if the E. 1.09 probability is 20% and 79 clients are in the sample? F. 12.64 What is the binomial variance when a client buys your extended G. 0.0625 warranty if the probability of buying is 20% and 79 clients are in the sample? H. 10/79 1. 1.90 J. 0.01 K. 3.56 L. 15.80 M. 2 N. 1.0 O. 0.91Hypothesis Data: A popular survey says the mean number of clients who use the organization website is 424. You want to prove it is less. Your sample of 100 shows a mean of 417 clients use the website with a standard deviation of 20. Use a 99% confidence level What is your alternative hypothesis? A. H1 is less than 417 What is the decision rule? B. -3.50 What is the test statistic? C. 1.65 Do you reject the null hypothesis? D. 3.50 E. 2.33 F. O G. Reject the null hypothesis H. Ho is less than 424 1. Do not reject the alternate hypothesis J. -2.33 K. Do not reject the null hypothesis L. Ho is less than 417 M. H1 is less than 424 N. Accept the alternate hypothesisYour Marketing Manager has industry sample data for 100 months of advertising spending. She asks you to estimate the mean industry advertising spending with a 90% confidence level. Use a mean of 50 and the standard deviation is 10. Provide the upper confidence interval