The permanganate ion is a powerful oxidizing agent that oxidizes water to oxygen under standard conditions.

MnO₄^1- (aq) + 8H₂O¹⁺ (aq) + 5e^- Mn²⁺ (aq) + 12H₂O (l) E = +1.507V

O₂ (g) + 4H₂O¹⁺ (aq) + 4e^- 6H₂O (l) E = +1.229V

What is the potential of a permanganate-oxygen cell operating at a pH = 7.00 with oxygen at a pressure of 0.200 atm, with [MnO₄^1-] = 0.100 M and [Mn²⁺] = 0.100 M?

Remember, E = E⁰ - (0.0592V/n)logQ