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The pOH of 0.23 M C6H5NH3* (Ka = 2.51 x 105) at 25C is: (Given that: C6H5NH3* + H20 C6H5NH2 + H3O*) . 9.35

The pOH of 0.23 M C6H5NH3* (Ka = 2.51 x 105) at 25C is: (Given that: C6H5NH3* + H20 C6H5NH2 + H3O*) . 9.35 O b. 2.60 . 8.53 O d. 11.4 . 10.5

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