The point P = (16, 5] lies fixed in place on the curve y = E | 2. Also on the curve is a variable point Q = (3:, w/E | 2], so the line PQ is the secant line between points P and Q. Round your answers to 5 decimal places. If it! = 16.1, the slope of 1319, is: I I and if I = 113.01, the slope of 1362 is: I I and if a: : 15.9, the slope of PQ is: I I and if I = 15.99, the slope of PQ is: I I Based on the above results, estimate the slope of the tangent line to the curve at 13(16, '5)