The reference:

Summary In this lesson, we studied collisions and explosions in two dimensions. In a two-dimensional collision or explosion, the total initial momentum is equal to the total final momentum. The total initial momentum before the collision (or explosion) in the x-direction, pxi, is equal to the total final momentum in the x-direction, Pxf, so that Pxi = Pxf. The total initial momentum before the collision (or explosion) in the y-direction, pyi, is equal to the total final momentum in the y-direction, Pyf, so that Pyi = Pyf. To determine the momentum and velocity of a mass m, after the collision, we can follow the following steps. 1. Determine the total initial x-component of the momentum before the collision (explosion): Pxi 2. Determine the total final x-component of the momentum after the collision (explosion): Pxf 3. Determine the final x-component of the momentum of m, after the collision (explosion): p1xf 4. Determine the total initial y-component of the momentum before the collision (explosion): Pyi 5. Determine the total final y-component of the momentum after the collision (explosion): Pxf 6. Determine the final y-component of the momentum of m, after the collision (explosion): plyf 7. The magnitude of the final momentum, P14, for m, is pif = VPixt + Plyf 8. The angle of this momentum vector is O = tan - Plyf Pixf 9. The magnitude of the final velocity is v1f = Pir m 10. The angle of the velocity vector is the same as the angle of the momentum vector.Question(s): 1. The physics of curling stone collisions and the conservation of momentum. Two identical curling stones of mass 19.5 kg collide. The stone my is moving at 5.00 m/s to the right towards a stationary stone of mass m,. The collision is a glancing collision. After the collision, one of the stones m1 moves at 3.50 m/s at an angle of 40.0 below the horizontal. a) What is the magnitude of the x-component momentum of m, after the collision? b) What is the magnitude of the y-component momentum of m, after the collision? c) What is the magnitude of the total momentum of m, after the collision? d) What is the direction of the total momentum of m, after the collision? e) What is the magnitude of the velocity of m, after the collision? f) What is the direction of the velocity of m, after the collision? Before the Collision After the Collision V= 5.00 m/s = 0.00 m/s m;=19.5 kg m;=19.5 kg \"~.\\_t.n.o-= my =19.5 kg Vi = 3.50 m/s 2. The physics of radioactive decay and the conservation of momentum. A nucleus, initially at rest, decays radioactively. In the process, it emits an electron horizontally to the east, with momentum 9.00 x 1021 kg . m/s and a "neutrina" horizontally to the south, with a momentum 4.80 x 102! kg . m/s. The mass of the residual nucleus is 3.60 x 1072 kg. a) What are the x-component and the y-components of momentum of the residual nucleus after the decay? b) What is the magnitude of the total momentum of the residual nucleus after the decay? c) What is the direction of the total momentum of the residual nucleus after the decay? d) What is the magnitude and velocity of the residual nucleus after the decay? After the Decay Pr=900x 10 kg - m/s electron neutrino p:=4.80 x 10* kg - m/s