The simulation (linked below) provides an interactive demonstration of integrating acceleration. The area shaded in purple in the simulation is equal to the definite integral of the plotted acceleration function between , and 2. In the simulation, t, = 0.5 s, while the value of 2 can be varied by the slider. Any shaded area that is below the time axis makes a negative contribution to the definite integral. Move the slider now to see the shaded area change. Simulation Definite integral of acceleration with respect to time The plot in the simulation describes a particle's acceleration. At the instant , the particle's velocity is v, = 0.5 m/s.Question 3 Can you use the information provided in the simulation to determine the velocity change for a time interval At = 12 - t,? What velocity change is necessary if the initial velocity is v1 = 0.5 m/s and the desired "final" velocity is V2 = 0? By adjusting the slider labeled "12", find the first instant to after , at which the particle is at rest. 12 = 5 eTextbook and Media Assistance Used Save for Later Last saved 16 minutes ago. Attempts: 1 of 7 used Submit Answer Saved work will be auto-submitted on the due date. Auto- submission can take up to 10 minutes. Using multiple attempts will impact your score. 5% score reduction after attempt 4ty (s) =4.990 4.990 + 10 a (m/'s') a dt = -11.3 m/s 0 It (s) A -5 -10 Definite integral of acceleration with respect to time This graphic provides an interactive demonstration of integrating acceleration. The area shaded in purple in the graphic is equal to the definite integral of the plotted acceleration function between 1 and t2. In the graphic, 1=0.5 s, while the value of ty can be varied by the slider. Any shaded area that is below the time axis makes a negative contribution to the definite integral