this is from chemical engineering corrosion course

Pr. 1 If you have a mixture of a) Cu+2/H b) Fe+2/H+ And you provide electrons for both mixtures, which ion will take the electrons in each mixture? (8 pints) Standard Potential (in volts) at 25C Electrode Reaction Au+ + 3e Au P12- + 2e" Pt Pd? + 2e = Pd Hg2+ + 2e Hg Ag + e- Ag. 2+ Hg2 + 2e 2Hg Cu + e Cu Cu2+ + 2e- Cu 2H+ + 2e H Pb2+ + 2e" - Pb Sn+ + 2e = Sn Mo'+ + 3e = Mo Ni2+ + 2e Ni Co2+ + 2e Co TI + e TI In + + 3e = In Cd2+ + 2e Cd Fe2+ + 2e Ga3+ + 3e = Ga Cr+ + 3e Cr Cr2+ + 2e Cr Zn2+ + 2e Zn Nb3+ + 3e = Nb Mn2+ + 2e Mn Zr+ + 4e Ti + 2e = Ti AP+ + 3e Hf4+ + 4e HE U3+ + 3e Be2+ + 2e- Mg2+ + 2e = Mg Na Na Ca+ + 2e = Ca 1.50 ca. 1.2 0.987 0.854 0.800 0.789 0.521 0.337 0.000 -0.126 -0.136 ca. -0.2 -0.250 -0.277 -0.336 -0.342 -0.403 -0.440 -0.53 -0.74 -0.91 -0.763 ca. - 1.1 -1.18 -1.53 -1.63 -1.66 -1.70 - 1.80 -1.85 -2.37 -2.71 -2.87 Fe = Zr - U Be e e 03 Table 5.1 (Continued) (volts) - - - -> FeO2- + 8H+ + 3e Fe+ + 4H2O CO3+ + Co2+ PbO2 + SO2- + 4H+ + 2e PbSO4 + 2H2O NiO2 + 4H+ + 2e Ni2+ + 2H2O Mn+ + e- Mn2- PbO2 + 4H + 2e Pb2+ + 2H2O Cl2 + 2e 2C1- Cr20,2- + 14H+ + 6e 2Cr + + 7H20 O2 + 4H+ + 4e 2H,0 Brz(1) + 2e" - 2Br Fe3+ + e Fe2+ O2 + 2H" + 2e H202 12 + 2e 21- O2 + 2H2O + 4e 40H HgCl2 + 2e 2Hg + 2CI AgCl + e Ag + CI SO2 + 4H+ + 2e H2SO3 + H2O Cu2+ + e Cu Sn+ + 2e Sna+ AgBr + e Ag + Br Cu(NH3)2+ + e Cu + 2NH, Ag(CN)2- + e Ag + 2CN PbSO, + 2e Pb + S022- HPbO2 + H2O + Pb + 3OH 2H20 + 2e H2 + 20H Zn(NH3)42+ + 2e Zn + 4NH, 1.9 1.82 1.685 1.68 1.51 1.455 1.3595 1.33 1.229 1.0652 0.771 0.682 0.5355 0.401 0.2676 0.222 0.17 0.153 0.15 0.095 -0.12 -0.31 -0.356 -0.54 -0.828 -1.03