This question has been posted but the answer given on this site leaves an error when compiling "No suitable method found for println(java.lang.String,)

My question is for Java as follows. Create a program that has an array of length 100 which will automatically be filled with randomly generated numbers between 1 and 100 each time the program is run. Have the program ask the user to enter a number between 1 and 100. Check to see if that number is one of the values in the array. If it is display We found your number XX at position YY in the array If the number is not in the array tell the user that no match was found.

The following is what I have so far, please advise what needs corrected to make this work for Java

import java.util.*; import java.lang.*; import java.io.*;

class Search { public static void main (String[] args) throws java.lang.Exception {

int[] array; for (int i = 0; i < 100; i++) { array[i] = 1 + (int)(Math.random() * 100); } Scanner sc=new Scanner(System.in); System.out.println("Enter number between 1 and 100"); int number=sc.nextInt(); for (int i = 0; i < 100; i++) { if (array[i] == number) { System.out.println("We found your number " , number, " at position ", i, " in the array"); } else { System.out.println("no match was found"); break; } } } }