TI = UK ( NI ) + T2 + 5x ( a) Ti = us ( 49 ) + T2 + ( 10) us ( 49 ) + T2 = 78 - 10 UK ( 49 ) + T2 = 68 Now For 3 kg Block" L to plane of contact No = 39 cos O N2 = 39 cas (25 ) No = 26.65 N 1/ to plane of contact 72 =1 3 9 sing + 1/K N2 + 30 T2 = 18.42 + UK ( 26 . 65 ) 2 New, using ( 1) and ( 2) UK ( 49 ) + 18 .42 + JK ( 26 . 65 ) = 68 UK = 68 - 18-42 49 + 26-65 UK = 0. 656 put value in 12 = 18 - 42 + 0 . 656 ( 26 . 65 ) T2 = 35.88 or 35.9 NSpring obeys flook's lace, so, fzkX JK =f = U .65x9.8 = 379 - 75 1/ m If it vies to lunch 2 79 ip ,2 7 x103 kg of ball the distance that it will reach hunt X = f - 2 - 7 X 10'S x g. 8 1 2 379- 75 12 0 00697 (m 2 mass ( m ) = tokg K= 60N / m EK [ K X * = 8 im . ( from equilibrium ] Tension ( T ) - W - k X 25 - w - weight J. .. =( 50 x 9 - 8) - (60 x 8. ) . KX - spring force CIONV = 120 km/ hy 3 m -20m - u = 120 km/hr - 33: 33 m /s UX = 3 3. 3 6 3150 2 - 32.20 m/c Uy 2 3 3 3 sinis $ 8. 6 m/ 28. Beat Ting of flight at it in . he will It = 2X 33 . 3 - Sin 15 - 1- 76 see Horizontal distance FORZ VAXRT = 32 - 2X 1.76 2 56. 4m. maximum hergle . , max. herguy at 2 _ H = Uyt + 1 972 2 . 2 ) 2 =3 -7 7 mc kelso , the height above end of ramp is 3.7 7m. but the height of wall abowe ramp is Im. So, the bike will clear the obstacle. and it will land (56 6 - 20) = 36.6m Far. from the wall . . Ut = D - 5 km/hy . It = 1.5 .15 km 2 t = 0. 125 hx Pitches Ball DV 2 = $1 74 m/s ....... t = 0.0Is Bar 40 In a duection . V. QBall 15 m / g V1 = 15m/S V2= 4205 24 cos40 JUNE 2 4 cos. 40 -( 15 ) 0 ...01 8338. 5 m / 3 2 24 sen 40 - 0 385. 67 m /s JULY 0 :01 Read. / ( 3.3 3.8 5) + (385.67)2 11294323-6 = 3360- 70 m/s ) d = rate x dime. SUNDAY 45010 = 2500 x 1 7 t - 86 for first half 46000 = loooxt t-20h for second half total time - 28 h There are live ways to go, using dirt = 2520 x14 = 35200 km or dinox 14 = 14060 km of FC flees I lime BC takes FC will cover. 49 bookm wheel exceeds the distance. Means Fe mill get there first . Lets be Clean, Lets be Civilized