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Total Latency Calculation for the 1 , 5 0 0 - byte packet: Given: Packet size ( P ) = 1 5 0 0 bytes

Total Latency Calculation for the 1,500-byte packet:
Given:
Packet size (
P)=1500 bytes
Link rate between routers (
R)=1.544 Mbps
Distance between routers (
D)=1600 km
Signal propagation velocity (
V
p
)=
2
\times
1
0
8
2\times 10
8
m/sec
Queuing delay at
1
R1(
1
Q1)=6 msec
Queuing delay at
2
R2(
2
Q2)=4 msec
Transmission Time (
T):
=
T=
R
P
Propagation Time (
P
t
):
=
P
t
=
V
p
D
Total Queuing Delay (
Q):
=
1
+
2
Q=Q1+Q2
Total Latency (
L):
=
+
+
L=T+P
t
+Q
=
1500
\times
8
1.544
\times
1
0
6
T=
1.544\times 10
6
1500\times 8
=
1600
\times
1
0
3
2
\times
1
0
8
P
t
=
2\times 10
8
1600\times 10
3
=
6
+
4
Q=6+4
=
+
+
L=T+P
t
+Q
Calculate each of these values and then plug them into the formula to find the total latency for the 1,500-byte packet.
b. Maximum Network Jitter Calculation for the five packets:
Given latency times for four additional packets: 17 msec, 36 msec, 11 msec, and 9 msec.
Calculate the Mean Latency (
M):
=
Latency times
Number of packets
M=
Number of packets
Latency times
Calculate the Jitter for each packet (
J):
=
Latency
J
i
=Latency
i
M
Find the Maximum Jitter:
Max Jitter
=
max
(
1
,
2
,
3
,
4
,
5
)
Max Jitter=max(J
1
,J
2
,J
3
,J
4
,J
5
)
Perform these calculations to find the maximum network jitter for the five packets.

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