In Problems 15 through 18, given information: Ms. Gilmore opened her saving account and deposited $1800 on 11/11/2012. On 11/11/2013, her balance was $1900, and she withdrew $100, giving a balance of $1800. On 11/11/2015, her balance was 2000, and she deposited $400, giving a balance of $2400. On 11/11/2016, she had a balance B $2800. 15. To find the Dollar-Weighted Yield Rate i = low, we have to solve an equation of 1800(1+1)* - 100(1+0)' + 400(1+1) = 2800 at t = 4. Which of the following equations at t=0 is the same as this equation at t = 4. a). 1800v* - 100v3 + 400 = 2800v b) 1800v2 - 100v2 + 400V = 2800 c). 1800 - 100v + 400 v2 = 2800 d. 1800 - 1000 + 400 == 28000 16. Find the Dollar-Weighted Yield Rate i by solving an equation of 1800(1+)- 100(1+0)' + 400(1+1) 2800 by Ti-Calculator, (Hint: Set Window: Xmin = 0, Xmax =0.10, Ymino, Ymax - 3000) a). 6.5% b). 7.5% c). 8.5% d). 9.5% 17. To find the Time-Weighted Yield Rate i = lrw, we need to find (1+1)(1+ 2) (1 + /3) a). (19/18)(20/19) (28/20) b). (19/18)(20/18)(28/24) c). (18/19)(19/20)(20/28) d) (28/18)(20/19) (24/18) 18. Find the Time-Weighted Yield Rate i = lrw= a). 9.055% b). 8.155% c).7.255% d). 6.355%