Two charges,

Q_(1)=2.20\\\\mu C

, and

Q_(2)=5.20\\\\mu C

are located at points

(0,-3.50cm)

and

(0,+3.50cm)

, as shown in the figure.\ What is the magnitude of the electric field at point

P

, located at

(5.00cm,0)

, due to

Q_(1)

alone?\

5.31\\\\times 10^(6)(N)/(C)

\ Computer's answer now shown above. You are correct. Your receipt no. is

158-6638

?\ Previous Tries\ What is the

x

-component of the total electric field at

P

?\ Submit Answer Tries 0/99\ What is the

y

-component of the total electric field at

P

?\ Submit Answer Tries 0/99\ What is the magnitude of the total electric field at P?\ Submit Answer Tries

(0)/(99)

\ Now let

Q_(2)=Q_(1)=2.20\\\\mu C

. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at

P

?\ Submit Answer Tries 0/99\ Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P?\ Submit Answer\ Tries 0/99

Two charges, Q1=2.20C, and Q2=5.20C are located at points (0,3.50cm) and (0,+3.50cm), as shown in the figur What is the magnitude of the electric field at point P, located at (5.00cm,0), due to Q1 alone? 5.31106N/C Computer's answer now shown above. You are correct. Your receipt no. is 158-6638 Previous Tries What is the x-component of the total electric field at P ? Tries 0/99 What is the y-component of the total electric field at P ? Tries 0/99 What is the maanitude of the total electric field at P? Tries 0/99 Now let Q2=Q1=2.20C. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P ? Tries 0/99 Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P? Tries 0/99