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UDP and TCP use 1 s complement for their checksums. Suppose that you have the following three 8 - bit bytes: 0 1 0 1

UDP and TCP use 1s complement for their checksums. Suppose that you
have the following three 8-bit bytes: 01010011,01100110,01110100. What is the 1s
complement of the sum of these 8-bit bytes? (Note that although UDP and TCP use
16-bit words in computing the checksum, for this problem you are being asked to
consider 8-bit sum.) Show all work. Why is it that UDP takes the 1s complement of
the sum: that is, why not just use the sum? With the 1s complement scheme, how
does the receiver detect errors? Is it possible that a 1-bit error will go undetected?
How about a 2-bit error?

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