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UpgradingfromaCISCtoaRISCmachinedecreasesthecyclesperinstruction by 2 0 % with a new clock rate that is 3 5 % faster. What is the speedup if no additional instructions are

UpgradingfromaCISCtoaRISCmachinedecreasesthecyclesperinstruction by 20% with a new clock rate that is 35% faster. What is the speedup if no additional instructions are needed? What is the maximum increase percentage in instruction count to achieve a speedup of 1.35? What is the maximum increase percentage in instruction count to achieve any speedup?

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