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URGENTTT Unknown Compound #1 : Molecular formula for Compound #1 is: C6H13NO2 : 13C NMR for Compound #1: Note that there are a total of

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Unknown Compound #1 : Molecular formula for Compound \#1 is: C6H13NO2 : 13C NMR for Compound \#1: Note that there are a total of 5 peaks in this spectrum, the two peaks around 60ppm are almost perfectly overlapped. 1 H NMR for Compound \#1. Note: The letters indicate the multiplicity, s= singlet, d= doublet, t = triplet, q = quartet, and m= multiplet. (four signals at 4.2,3.2,2.4 and 1.3ppm ), What is the index of unsaturation of Compound if 1 ? Question 2 1 pts Based on the spectroscopic data for Compound \#t, which of of the following functional groups are NOT present in the correct structure that matches this data? Select AlL that apply. Petone Anine = Aratiol Cubconslic airit Etheir Aricide Look at the "H NMR for Compound 11 . Notice the signals at 4.2 and 1.3ppm. These two signals represent a common pattern/arrangement of atoms. What pattern do these peaks represent? Ethyl group Pheny group Propyl group Isopropyl group Tert-butyl group Sec-butyl group Question 4 1 pts Consider the IR of Compound \#1. What type of bond is most likely represented by the peak at 1189cm1 ? sp2CO( single bond to O) spgC.O sp2C=O (double bond to O ) sp2C=C sp3C-H sp2CH Consider the 1Hi NMR of Compound 1. Consider the signats at 4.2 and 1,3 ppm. Why is the signal at 4.2ppm farther downthed compared to the signal at i.3 ppm? The signal at 4.3 pom is close to ath electronezattive aturti. rabing its checnical shift. The signal at 4.3 ppen represents protonis attected to a pi bond, rasing its chemical shift. The signal at 4.3ppm has a higher multiplity, muking its chemical shift targer. The agral at 4.3 ppin represents protoms attached to a C=0 group, raising its chemical shift. None of the answer choices explains the difference in chernical shift. Question 6 5 pts Which structure below best matches the spectroscopic data provided for Compound \#1? A. B. C. D. E F. G. H. 1. J. K L. M. N. 0

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