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use the fundamental theorem of calculus to find G'(x) if G(x)= (int_{1}^{x^2} cos t dt) a. (G'(x) = int_{1}^{x^2} -sin t dt) b. (G'(x) =
use the fundamental theorem of calculus to find G'(x) if G(x)=
\(\int_{1}^{x^2} cos t dt\)
a. \(G'(x) = \int_{1}^{x^2} -sin t dt\)
b. \(G'(x) = \int_{1}^{x^2} sin t dt\)
c. G'(x) = -2x sin x^2
d. G'(x) = 2x cos x^2
e none of the above
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