Use the fundamental theorem of calculus to solve the integral equation. 6) 2x y(x) = 4 - 3t - ty(t)dt 0dy = da -andy 3- y (2 ) 3- 109 ( 3 y ) = - 2712 C 2dy 3 - y ( x ) dy = - 2 / 2 dn 3 - y ( 21 ) idu logn and. in an - - logy and sidn = 21 2 + c = ) log ( 3 - y (n1 ) ( - 1 ) = - 2.12 + C 2 - - log ( 3 - 4 ( m ) ) = - 21 2 + c , =) - log ( 3 - y (n ) ) = - (212+ c ; ) 7 log ( 3 - you ) ) = 212 + c 7 3 - y (n ) s p ( 212 + ci ) 7 3 - y ( 2 ) 5 0 72 . e G ' 3 3 - y (n ) = er. c y (n) = 3 - cenzy