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use this data for B and L B= 22500 bits/sec L=6000 The following parameters are defined for a switching network: N = 4 = number
use this data for B and L B= 22500 bits/sec L=6000
The following parameters are defined for a switching network: N = 4 = number of hops between two given end systems L = 6000 = message length in bits B = data rate, in bits per second (bps), on all links P = 1080 = fixed packet size, in bits H = 80 = overhead (header) bits per packet S = 0.2 = call setup time (circuit switching or virtual circuit) in seconds T = 0.02 = call teardown time (circuit switching or virtual circuit) in seconds D = 0.001 = propagation delay per hop in seconds Relevant equations (6 +10) CAT + N -1) +ND S+ ( +Tvo) (+N-1 + N - 1) +ND+T S+B+ND+T Use the scenario from Problem (2), except there is a nonzero processing delay for both virtual circuit switching (Tproc = Tyc) and datagram switching (Tproc = TD). Assume the processing delay for a virtual circuit switching at each node is Tyc=0.001 seconds. Now compare with datagram packet switching. Find the minimum datagram processing delay (TD) for which virtual circuit switching has a lower end-to-end delay than datagram packet switching. Use setup time=0.2 sec. and teardown time=0.02 sec. You must include both setup and teardown timeStep by Step Solution
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