Question
using 8086 assembly language write a program which will: Display an appropriate prompt. Input a signed base 8 integer from the keyboard If an invalid
using 8086 assembly language
write a program which will:
Display an appropriate prompt.
Input a signed base 8 integer from the keyboard
If an invalid character (that is, not in the range '0'-'7') is input, erase the character by printing a backspace char (ASCII code 8), a blank (' ') and another backspace and do not attempt to convert the invalid character.
Convert the characters as they are input into the equivalent binary number stored in register BX
Overflow processing is NOT necessary.
Display another appropriate prompt.
Output the base-2 form of the binary number in register BX.
If the user indicates a negative number is being input, remember that fact, read the number as an absolute value, then negate it when input is finished.
Sample input/output:
Enter a base-8 number: 10 The binary number is: 0000000000001000
Another input/output sample:
Enter a base-8 number: -1234 The binary number is: 1111110101100100
.asm
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