Question
Using data from the 2012 season for MLB a baseball analytics firm wants to determine which variable are important in predicting a teams wins. The
Using data from the 2012 season for MLB a baseball analytics firm wants to determine which variable are important in predicting a teams wins. The data collected in clues wins, earned run average (ERA), and runs scored for the 2012 season. The firm also has each team categorized as being in the 0=American league or 1= National league.
The first thing the firm does is runs a model to predict wins based on ERA and number of runs scored. The Summary output is below.
SUMMARY OUTPUT | |||||
Regression Statistics | |||||
Multiple R | 0.961591 | ||||
R Square | 0.924658 | ||||
Adjusted R Square | 0.919077 | ||||
Standard Error | 3.394783 | ||||
Observations | 30 | ||||
ANOVA | |||||
df | SS | MS | F | Significance F | |
Regression | 2 | 3818.837 | 1909.419 | 165.6827 | 6.92E-16 |
Residual | 27 | 311.1629 | 11.52455 | ||
Total | 29 | 4130 | |||
Coefficients | Standard Error | t Stat | P-value | ||
Intercept | 83.04052 | 9.265717 | 8.962126 | 1.41E-09 | |
E.R.A. | -19.0864 | 1.257472 | -15.1783 | 9.66E-15 | |
Runs Scored | 0.106277 | 0.010911 | 9.740068 | 2.49E-10 |
What is the regression model equation
Group of answer choices
Wins = -19.08 (ERA) + 0.106 (Runs Scored)
Wins = -19.08 (ERA) + 0.106 (Runs Scored) + 83.04
-19.08 (ERA) = 0.106 (Runs Scored)
Wins = 8.96 + -15.18 (ERA) + 9.74 (Runs Scored)
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